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Maths olympiad question · P5–P6★★★ Hard

Averages: olympiad question 8

A hard question on averages for P5–P6, with a step-by-step solution, diagrams and the answer. Averages appear in the Hua Xia Cup's P4 and P5 first rounds, qualifying rounds and finals.

The question

Classes A and B both enter a maths contest.

Class A averages 74, class B averages 69, and the two classes together average 73.

Class A has 33 more pupils than class B.

How many pupils are in class A?

Show the hints (3)
  1. Hint 1: How far above the combined average is each pupil in A, on average? How far below is each in B?
  2. Hint 2: What class A has above the combined average exactly makes up what class B is below it. Use that to find the ratio of the class sizes.
  3. Hint 3: Class A : class B = 4 : 1, and they differ by 33 pupils.

Worked solution

Have a go first, then read the solution step by step.

  1. 1.Each pupil in A is 74 − 73 = 1 above on average; each in B is 73 − 69 = 4 below.
  2. 2.What A has above exactly fills what B is below: A's size × 1 = B's size × 4, so A : B = 4 : 1.
  3. 3.The difference, 4 − 1 = 3 parts, is 33 pupils, so one part is 33 ÷ 3 = 11.
  4. 4.Class A = 4 × 11 = 44. (B has 11: 74 × 44 + 69 × 11 = 73 × 55.)
  5. ⚠️Common mistake: turning the ratio upside down. The class whose average is closer to the combined average is the bigger one.

Answer: 44 pupils

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