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Maths olympiad question · P5★★ Medium

Divisibility and factors: olympiad question 5

A medium question on divisibility and factors for P5, with a step-by-step solution, diagrams and the answer. Common in the Hua Xia Cup's P4 and P5 qualifying rounds and finals; harder ones use how many factors a number has, and square numbers.

The question

The school hall needs 52 chairs set out in a rectangle: every row has the same number of chairs, and all the chairs are used.

There must be at least 2 rows and at least 2 chairs in each row.

"2 rows of 26" and "26 rows of 2" count as two different arrangements.

How many arrangements are there?

Show the hints (2)
  1. Hint 1: Rows times chairs per row must make 52. Which numbers can the number of rows be?
  2. Hint 2: List every factor of 52, then think about which numbers of rows aren't allowed.

Worked solution

Have a go first, then read the solution step by step.

  1. 1.The number of rows must be a factor of 52: 1, 2, 4, 13, 26, 52 — 6 of them. Each pair, top times bottom, makes 52: 2 rows means 26 in each.
  2. 2.1 row (of 52) is not allowed, and neither is 52 rows (of 1).
  3. 3.6 − 2 = 4.
  4. ⚠️Common mistake: treating 2 rows and 26 rows as the same and counting half, or forgetting to drop 1 row and 52 rows.

Answer: 4 arrangements

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