Numsprite數靈精Play free
中文

Maths olympiad question · P6★★★ Hard

Percentages and mixtures: olympiad question 6

A hard question on percentages and mixtures for P6, with a step-by-step solution, diagrams and the answer. Common in the Hua Xia Cup's P6 first round and finals: discounts, a rise followed by a fall, and mixtures.

The question

A dessert shop's chef has prepared a big jug of 1900 g of sugar water at 20% for sweetening.

After 1000 g has been used, the chef finds it not sweet enough and decides to add sugar to what is left in the jug to raise the concentration to 36%.

How many grams of sugar must the chef add?

Show the hints (3)
  1. Hint 1: After some sugar water is used, has the concentration of what is left changed?
  2. Hint 2: When sugar is added, the sugar goes up — but what stays the same?
  3. Hint 3: 900 g is left, of which 720 g is water; after adding sugar, water is 64% of the solution.

Worked solution

Have a go first, then read the solution step by step.

  1. 1.Using some doesn't change the concentration: 1900 − 1000 = 900 g is left, still at 20%.
  2. 2.Water is 100% − 20% = 80% of it: 900 × 80 ÷ 100 = 720 g. Adding sugar doesn't change the water.
  3. 3.After adding sugar, the water is 100% − 36% = 64%: the solution weighs 720 × 100 ÷ 64 = 1125 g.
  4. 4.Sugar to add = 1125 − 900 = 225 g.
  5. 5.Check: the sugar goes from 180 g to 180 + 225 = 405 g, and 405 × 100 ÷ 1125 = 36 ✓
  6. ⚠️Common mistake: keeping the total fixed and working out 900 × (36 − 20) ÷ 100 = 144. The added sugar makes the solution heavier too; what stays the same is the water.

Answer: 225 g

Play more like this in Numsprite (unlimited questions, instant marking) →A free maths game: every level free from Easy to Expert (★ to ★★★★), unlimited questions, no download