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Maths olympiad question · P3–P4★ Easy

Meeting: olympiad question 1

An easy question on meeting for P3–P4, with a step-by-step solution, diagrams and the answer. The basis of journey problems: meeting and catching up appear in the Hua Xia Cup's P4 to P6 qualifying rounds and finals.

The question

Ming and May stand at opposite ends of the playground, 15 m apart.

They set off at the same moment and run straight towards each other.

Ming runs 3 m a second and May 2 m a second.

After how many seconds do they meet?

Show the hints (2)
  1. Hint 1: Each second, how much shorter does the distance between them get?
  2. Hint 2: Together they have to close all 15 m.

Worked solution

Have a go first, then read the solution step by step.

  1. 1.Each second Ming runs 3 m and May 2 m: together they close 3 + 2 = 5 m.
  2. 2.The 15 m gap shrinks by 5 m a second: 15 ÷ 5 = 3, so they meet after 3 seconds.
  3. ⚠️Common mistake: dividing by one runner's speed. Both are running, so they close the gap together.

Answer: 3 seconds

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