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Centres of a triangle · Ages 14–15

The angle bisector's property

A point on the bisector is equally far (perpendicularly) from both arms.

How to do it

Method

A point on the bisector is equally far (perpendicularly) from both arms

PM = 3 cm: PN = 3 cm, ∠POM = 70° ÷ 2 = 35°

Another way

By congruent triangles

△OPM ≅ △OPN (AAS), PM = PN

In full

The angle bisector theorem: any point on an angle's bisector is the same distance from the angle's two arms (∠ bisector theorem). Distance means the perpendicular: drop perpendiculars from P to OA and OB, feet M and N, and PM = PN. The converse: a point equally far from the two arms lies on the bisector (converse of ∠ bisector theorem). One way: use the theorem straight. ∠AOB = 70°, P on the bisector and PM = 3 cm give PN = 3 cm and ∠POM = 70° ÷ 2 = 35°. Another: prove it by congruent triangles. In △OPM and △OPN, ∠PMO = ∠PNO = 90°, ∠POM = ∠PON and OP is common, so △OPM ≅ △OPN (AAS) and PM = PN. Careful: the distance is the perpendicular, not P to O or P to just any point of an arm.

Worked examples

Have a go first, then open each one for the answer and the working.

  1. Example 1

    In the picture, OP bisects ∠AOB. x =

    Show the answer and working

    Answer: 45°

    A bisector cuts the angle into two equal halves: x = 45°.

  2. Example 2

    A point P is 8 cm and 8 cm from the two arms of ∠AOB, measured at right angles. P lies on the bisector of ∠AOB.

    True or false?

    Show the answer and working

    Answer: True

    Only a point equally far from both arms lies on the bisector (converse of ∠ bisector theorem).

  3. Example 3

    P is on the bisector of ∠AOB, PM ⊥ OA and PN ⊥ OB, with OP = 5 cm and OM = 4 cm. PN =

    Show the answer and working

    Answer: 3 cm

    PM = 52 − 42 = 3 cm (Pyth. thm.); PN = PM = 3 cm (∠ bisector theorem).

Practice questions to try

Try these 5; the answers are at the end. For a whole worksheet, see VIP worksheets below.

  1. 1.In the picture, OP bisects ∠AOB. x =

    Answer:

  2. 2.In the picture, OP bisects ∠AOB, PM ⊥ OA and PN ⊥ OB. So PM = PN ( ? ). Which reason goes in the gap?

    • A. given
    • B. converse of ∠ bisector theorem
    • C. ∠ bisector theorem
    • D. ⊥ bisector theorem

    Choose the right answer

    Answer:

  3. 3.In the picture, OP bisects ∠AOB, ∠AOB = 82° and PM ⊥ OA. x =

    Answer:

  4. 4.P lies inside ∠AOB with PM ⊥ OA, PN ⊥ OB, PM = PN = 9 cm and ∠AOB = 92°. ∠POM = °, ∠OPM = °

    Fill in each blank

    Answer:

  5. 5.P is on the bisector of ∠AOB, PM ⊥ OA and PN ⊥ OB, with OP = 75 cm and OM = 72 cm. PN =

    Answer:

All the answers
  1. 1. 50°
  2. 2. C. ∠ bisector theorem
  3. 3. 49°
  4. 4. 46, 44
  5. 5. 21 cm
Free worksheet: The angle bisector's propertyWorking out, multiple choice and word problems, with answers and working, to print or save as a PDF

VIP practice notes and papers

Aimed at tests and exams: questions on this topic, new every time, to print or save as a PDF.

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