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Percentages (II) · Ages 13–14

Growth and depreciation

Growth: times (1 + r%)n. Depreciation: times (1 − r%)n.

How to do it

Method

Growth: times (1 + r%)^n. Depreciation: times (1 − r%)^n

200000 × 0.93 = 145800

Another way

Year by year

200000 → 180000 → 162000 → 145800

In full

Growing by the same percentage every year, the value after n years = the start × (1 + r%)n; losing the same percentage every year (depreciating), the value after n years = the start × (1 − r%)n. A $200000 car loses 10% of its value a year: one way, the formula, after 3 years it is worth 200000 × 0.93 = $145800; another, year by year, 200000 → 180000 → 162000 → 145800. That is 1 − 0.729 = 27.1% lost in all, not 3 × 10% = 30%: each year's 10% is of that year's lower value. Back from the value after n years to the start: divide by (1 ± r%)n. Asked in which year it first passes (or falls below) an amount, multiply year by year until it does.

Worked examples

Have a go first, then open each one for the answer and the working.

  1. Example 1

    A city of 100000 people grows 5% a year. To the nearest whole number, how many people will it have after 3 years?

    Show the answer and working

    Answer: 115763 people

    100000 × (1 + 5%)3 = 100000 × 1.053, about 115763 people.

  2. Example 2

    A machine loses 10% of its value each year. After 6 years, its value is its first value times which of these?

    • A. 0.16
    • B. 1 − 0.1 × 6
    • C. 0.96
    • D. 0.9 × 6

    Choose the right answer

    Show the answer and working

    Answer: C. 0.96

    Each year leaves 1 − 10% = 0.9 of it; over 6 years, 0.96.

  3. Example 3

    A new car worth $280,000 loses 20% of its value in its first year and 12% a year after that. To the nearest dollar, what is it worth after 3 years?

    Show the answer and working

    Answer: 173,466 dollars

    The first year leaves 1 − 20%, each of the next 2 years 1 − 12%: 280000 × (1 − 20%) × (1 − 12%)2, about 173466.

Practice questions to try

Try these 5; the answers are at the end. For a whole worksheet, see VIP worksheets below.

  1. 1.A number grows 10% a year, so in 3 years it has grown 30% in all.

    True or false?

    Answer:

  2. 2.A machine loses 20% of its value each year. After 4 years, its value is its first value times which of these?

    • A. 0.84
    • B. 0.24
    • C. 0.8 × 4
    • D. 1 − 0.2 × 4

    Choose the right answer

    Answer:

  3. 3.A website has 5000 members, and the number grows 10% a year. At the end of which year does it first pass 15000?

    • A. The end of year 13
    • B. The end of year 20
    • C. The end of year 12
    • D. The end of year 11

    Choose the right answer

    Answer:

  4. 4.A machine loses 20% of its value a year and is worth $112,640 after 3 years. What was it worth new?

    Answer:

  5. 5.A new car worth $310,000 loses 25% of its value in its first year and 10% a year after that. To the nearest dollar, what is it worth after 3 years?

    Answer:

All the answers
  1. 1. False
  2. 2. A. 0.84
  3. 3. C. The end of year 12
  4. 4. 220,000 dollars
  5. 5. 188,325 dollars
Free worksheet: Growth and depreciationWorking out, multiple choice and word problems, with answers and working, to print or save as a PDF

VIP practice notes and papers

Aimed at tests and exams: questions on this topic, new every time, to print or save as a PDF.

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