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Multiplying, dividing and mixed operations · Ages 7–8

Division with remainders worksheet

Part of: Division: sharing, grouping and remainders

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Division with remainders worksheet

Multiplying, dividing and mixed operations · Ages 7–8

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Name:Date:Score:/48

Write each answer in the space. For word problems, show your working and write a sentence answer.

Part A: Working out and filling in (2 marks each)

  1. 1.92 ÷ 8 → rem ?

    Answer:

  2. 2.38 ÷ 5 → rem ?

    Answer:

  3. 3.8 ÷ 3 → rem ?

    Answer:

  4. 4.37 ÷ 4 → rem ?

    Answer:

  5. 5.45 ÷ 6 → rem ?

    Answer:

  6. 6.28 ÷ 8 → rem ?

    Answer:

  7. 7.30 ÷ 7 → rem ?

    Answer:

  8. 8.79 ÷ 7 → rem ?

    Answer:

  9. 9.43 ÷ 6 → rem ?

    Answer:

  10. 10.76 ÷ 7 → rem ?

    Answer:

  11. 11.26 ÷ 3 → rem ?

    Answer:

  12. 12.20 ÷ 8 → rem ?

    Answer:

Part B: Word problems (4 marks each)

  1. 13.45 shells are shared equally among 4 children. At most, how many shells can each child get?

    Working:

    Answer:

  2. 14.48 pencils are shared equally among 5 children. At most, how many pencils can each child get?

    Working:

    Answer:

  3. 15.62 sweets are shared equally among 7 children, each getting as many as possible. How many sweets are left over?

    Working:

    Answer:

  4. 16.84 pencils are shared equally among 9 children, each getting as many as possible. How many pencils are left over?

    Working:

    Answer:

  5. 17.30 pupils go boating, and each boat takes at most 4. What is the smallest number of boats they need so that everyone can get on?

    Working:

    Answer:

  6. 18.15 pupils go boating, and each boat takes at most 6. What is the smallest number of boats they need so that everyone can get on?

    Working:

    Answer:

Show the answers and working

Division with remainders worksheet: Answers and working

Part A: Working out and filling in

  1. 1. 92 ÷ 8 → rem 4

    92 ÷ 8: the largest multiple of 8 not past 92 is 8 × 11 = 88, 92 − 88 = 4, so the remainder is 4

  2. 2. 38 ÷ 5 → rem 3

    38 ÷ 5: the largest multiple of 5 not past 38 is 5 × 7 = 35, 38 − 35 = 3, so the remainder is 3

  3. 3. 8 ÷ 3 → rem 2

    8 ÷ 3: the largest multiple of 3 not past 8 is 3 × 2 = 6, 8 − 6 = 2, so the remainder is 2

  4. 4. 37 ÷ 4 → rem 1

    37 ÷ 4: the largest multiple of 4 not past 37 is 4 × 9 = 36, 37 − 36 = 1, so the remainder is 1

  5. 5. 45 ÷ 6 → rem 3

    45 ÷ 6: the largest multiple of 6 not past 45 is 6 × 7 = 42, 45 − 42 = 3, so the remainder is 3

  6. 6. 28 ÷ 8 → rem 4

    28 ÷ 8: the largest multiple of 8 not past 28 is 8 × 3 = 24, 28 − 24 = 4, so the remainder is 4

  7. 7. 30 ÷ 7 → rem 2

    30 ÷ 7: the largest multiple of 7 not past 30 is 7 × 4 = 28, 30 − 28 = 2, so the remainder is 2

  8. 8. 79 ÷ 7 → rem 2

    79 ÷ 7: the largest multiple of 7 not past 79 is 7 × 11 = 77, 79 − 77 = 2, so the remainder is 2

  9. 9. 43 ÷ 6 → rem 1

    43 ÷ 6: the largest multiple of 6 not past 43 is 6 × 7 = 42, 43 − 42 = 1, so the remainder is 1

  10. 10. 76 ÷ 7 → rem 6

    76 ÷ 7: the largest multiple of 7 not past 76 is 7 × 10 = 70, 76 − 70 = 6, so the remainder is 6

  11. 11. 26 ÷ 3 → rem 2

    26 ÷ 3: the largest multiple of 3 not past 26 is 3 × 8 = 24, 26 − 24 = 2, so the remainder is 2

  12. 12. 20 ÷ 8 → rem 4

    20 ÷ 8: the largest multiple of 8 not past 20 is 8 × 2 = 16, 20 − 16 = 4, so the remainder is 4

Part B: Word problems

Marking: 2 for the working, 1 for the answer, 1 for the sentence.

  1. 13. 45 shells are shared equally among 4 children. At most, how many shells can each child get? (Answer: 11 shells)

    45 ÷ 4 = 11 R 1

  2. 14. 48 pencils are shared equally among 5 children. At most, how many pencils can each child get? (Answer: 9 pencils)

    48 ÷ 5 = 9 R 3

  3. 15. 62 sweets are shared equally among 7 children, each getting as many as possible. How many sweets are left over? (Answer: 6 sweets)

    62 ÷ 7 = 8 R 6

  4. 16. 84 pencils are shared equally among 9 children, each getting as many as possible. How many pencils are left over? (Answer: 3 pencils)

    84 ÷ 9 = 9 R 3

  5. 17. 30 pupils go boating, and each boat takes at most 4. What is the smallest number of boats they need so that everyone can get on? (Answer: 8 boats)

    30 ÷ 4 = 7 R 2; the 2 left over need a boat too: 7 + 1 = 8

  6. 18. 15 pupils go boating, and each boat takes at most 6. What is the smallest number of boats they need so that everyone can get on? (Answer: 3 boats)

    15 ÷ 6 = 2 R 3; the 3 left over need a boat too: 2 + 1 = 3

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